Introduction to the integral of 1/x^3
In calculus, the integral is a fundamental concept that assigns numbers to functions to define displacement, area, volume, and all those functions that contain a combination of tiny elements. It is categorized into two parts, definite integral and indefinite integral. The process of integration calculates the integrals. This process is defined as finding an antiderivative of a function.
Integrals can handle almost all functions, such as trigonometric, algebraic, exponential, logarithmic, etc. This article will teach you what is integral to an algebraic function 1/x3. You will also understand how to compute 1 by x^3 integral by using different integration techniques.
What is the integral of 1/x^3?
The integral of 1/x^3 is an antiderivative of the 1/x^3 function which is equal to the negative of 1/2x^2. It is also known as the reverse derivative of the function 1/x^3 which is an algebraic function. It can be calculated by using the power rule of integral. This rule is written as;
$\int x^n dx=\frac{x^{n+1}}{n+1}+c$
This formula says that the integral of any algebraic function with some exponent, can be calculated by adding 1 in its exponent and dividing by the new exponent i.e n+1.
Integral of 1 by x^3 formula
The formula of integral of 1 x 3 cube contains integral sign, coefficient of integration and the function as 1/x^3. It is denoted by ∫(1/x^3)dx. In mathematical form, the integral of 1/x^3 is:
$\int \frac{1}{x^3}dx = -\frac{1}{2x^2}+c$
Where c is any constant involved, dx is the coefficient of integration and ∫ is the symbol of integral.
How to calculate the integral of 1/x3?
The integral of 1 by x^3 is its antiderivative that can be calculated by using different integration techniques. In this article, we will discuss how to calculate integral of x^-3 by using:
- Integration by parts
- Definite integral
Integral 1/x3 by using integration by parts
The derivative of a function calculates the rate of change, and integration is the process of finding the antiderivative of a function. The integration by parts is a method of solving the integral of two functions combined together. Let’s discuss calculating the integral of 1 by x3 by using integration by parts.
Proof of integral of 1/x3 by using integration by parts
To find the integral 1/(x^3) using integration by parts, we can use the following formula:
$I=f(x)\int g(x)dx-\int[\frac{d}{dx}(f(x))\int g(x)dx]dx$
Suppose that,
$f(x) = \frac{1}{x^3}$
$g(x) =1{2}nbsp;
Using these values in the above formula,
$I=\frac{1}{x^3}\int 1 dx-\int [\frac{d}{dx}(\frac{1}{x^3})\int 1dx]dx$
Integrating,
$I=\frac{1}{x^3}\times x - \int[\frac{-3}{x^4}\times x]dx$
$I =\frac{1}{x^2}+3\int \frac{1}{x^3}dx$
$I=\frac{1}{x^2}+3\frac{x^{-3+1}}{-3+1}$
$I=\frac{1}{x^2}-\frac{3}{2x^2}$
$I=\frac{-1}{2x^2}+c$
Hence the integral of 1 x3 by using by parts integration calculator is -1/2x^2+c, where c is a constant known as an integration constant.
1/x3 integration by using definite integral
The definite integral is a type of integral that calculates the area of a curve by using infinitesimal area elements between two points. The definite integral can be written as:
$\int \int^b_a f(x)dx = F(b)-F(a)$
Let’s understand the verification of the integral of 1/x^3 by using the definite integral.
Proof of integral 1/x3 by using definite integral
To compute the integral of 1/x3 by using a definite integral, we can use the interval from a to b. It means that we can evaluate the definite integral of x square for any value of a and b. Let’s compute it from 1 to 2.
$\int^b_a \frac{1}{x^3}dx= \left|\frac{-1}{2x^2}\right|^2_1$
Substituting the values of upper and lower bounds.
$\int^2_1 \frac{1}{x^3}dx=-\frac{1}{2(2)^2}+\frac{1}{2(1)}$
$\int^2_1 \frac{1}{x^3}dx=-\frac{1}{8}+\frac{1}{2}$
$\int^2_1 \frac{1}{x^3}dx=-\frac{3}{8}$
For any value of a and b, we can evaluate the definite integral by using the above formula. You can also use our definite integral calculator to make this calculation simple in just one click.
Frequently Asked Questions
How to integrate 1 x 3?
To integrate 1/x3, we can use the power rule of integration. In this rule, we add 1 in the power of x and divide it by the new power that is,
$\int \frac{1}{x^3}dx=\frac{x^{-3+1}}{-3+1}=\frac{-1}{2x^2}$
What is the integration of x 3dx?
The integration of x^3 can be calculated by using the power rule of integrals. It is equal to the ratio between x^4 and 4. Mathematically, we can write it as:
$\int x^3dx=\frac{x^{3+1}}{3+1}=\frac{x^4}{4}+c$
